4(a^2+5a-6)-3(2a^3+4a-5)=0

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Solution for 4(a^2+5a-6)-3(2a^3+4a-5)=0 equation: 


Simplifying
4(a2 + 5a + -6) + -3(2a3 + 4a + -5) = 0

Reorder the terms:
4(-6 + 5a + a2) + -3(2a3 + 4a + -5) = 0
(-6 * 4 + 5a * 4 + a2 * 4) + -3(2a3 + 4a + -5) = 0
(-24 + 20a + 4a2) + -3(2a3 + 4a + -5) = 0

Reorder the terms:
-24 + 20a + 4a2 + -3(-5 + 4a + 2a3) = 0
-24 + 20a + 4a2 + (-5 * -3 + 4a * -3 + 2a3 * -3) = 0
-24 + 20a + 4a2 + (15 + -12a + -6a3) = 0

Reorder the terms:
-24 + 15 + 20a + -12a + 4a2 + -6a3 = 0

Combine like terms: -24 + 15 = -9
-9 + 20a + -12a + 4a2 + -6a3 = 0

Combine like terms: 20a + -12a = 8a
-9 + 8a + 4a2 + -6a3 = 0

Solving
-9 + 8a + 4a2 + -6a3 = 0

Solving for variable 'a'.

The solution to this equation could not be determined.

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